Optimal. Leaf size=181 \[ -\frac{A b-a B}{b (a+b x) (d+e x)^{3/2} (b d-a e)}+\frac{3 a B e-5 A b e+2 b B d}{\sqrt{d+e x} (b d-a e)^3}+\frac{3 a B e-5 A b e+2 b B d}{3 b (d+e x)^{3/2} (b d-a e)^2}-\frac{\sqrt{b} (3 a B e-5 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{7/2}} \]
[Out]
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Rubi [A] time = 0.385207, antiderivative size = 181, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182 \[ -\frac{A b-a B}{b (a+b x) (d+e x)^{3/2} (b d-a e)}+\frac{3 a B e-5 A b e+2 b B d}{\sqrt{d+e x} (b d-a e)^3}+\frac{3 a B e-5 A b e+2 b B d}{3 b (d+e x)^{3/2} (b d-a e)^2}-\frac{\sqrt{b} (3 a B e-5 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{7/2}} \]
Antiderivative was successfully verified.
[In] Int[(A + B*x)/((a + b*x)^2*(d + e*x)^(5/2)),x]
[Out]
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Rubi in Sympy [A] time = 41.7624, size = 167, normalized size = 0.92 \[ \frac{\sqrt{b} \left (5 A b e - 3 B a e - 2 B b d\right ) \operatorname{atan}{\left (\frac{\sqrt{b} \sqrt{d + e x}}{\sqrt{a e - b d}} \right )}}{\left (a e - b d\right )^{\frac{7}{2}}} + \frac{5 A b e - 3 B a e - 2 B b d}{\sqrt{d + e x} \left (a e - b d\right )^{3}} - \frac{5 A b e - 3 B a e - 2 B b d}{3 b \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )^{2}} + \frac{A b - B a}{b \left (a + b x\right ) \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)/(b*x+a)**2/(e*x+d)**(5/2),x)
[Out]
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Mathematica [A] time = 0.874896, size = 154, normalized size = 0.85 \[ \frac{\sqrt{d+e x} \left (\frac{6 (a B e-2 A b e+b B d)}{d+e x}+\frac{2 (b d-a e) (B d-A e)}{(d+e x)^2}+\frac{3 b (a B-A b)}{a+b x}\right )}{3 (b d-a e)^3}-\frac{\sqrt{b} (3 a B e-5 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{7/2}} \]
Antiderivative was successfully verified.
[In] Integrate[(A + B*x)/((a + b*x)^2*(d + e*x)^(5/2)),x]
[Out]
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Maple [B] time = 0.03, size = 328, normalized size = 1.8 \[ -{\frac{2\,Ae}{3\, \left ( ae-bd \right ) ^{2}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}+{\frac{2\,Bd}{3\, \left ( ae-bd \right ) ^{2}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}+4\,{\frac{Abe}{ \left ( ae-bd \right ) ^{3}\sqrt{ex+d}}}-2\,{\frac{Bae}{ \left ( ae-bd \right ) ^{3}\sqrt{ex+d}}}-2\,{\frac{Bbd}{ \left ( ae-bd \right ) ^{3}\sqrt{ex+d}}}+{\frac{A{b}^{2}e}{ \left ( ae-bd \right ) ^{3} \left ( bxe+ae \right ) }\sqrt{ex+d}}-{\frac{Babe}{ \left ( ae-bd \right ) ^{3} \left ( bxe+ae \right ) }\sqrt{ex+d}}+5\,{\frac{A{b}^{2}e}{ \left ( ae-bd \right ) ^{3}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }-3\,{\frac{Babe}{ \left ( ae-bd \right ) ^{3}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }-2\,{\frac{{b}^{2}Bd}{ \left ( ae-bd \right ) ^{3}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)/(b*x+a)^2/(e*x+d)^(5/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x + a)^2*(e*x + d)^(5/2)),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.229689, size = 1, normalized size = 0.01 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x + a)^2*(e*x + d)^(5/2)),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)/(b*x+a)**2/(e*x+d)**(5/2),x)
[Out]
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GIAC/XCAS [A] time = 0.232987, size = 401, normalized size = 2.22 \[ \frac{{\left (2 \, B b^{2} d + 3 \, B a b e - 5 \, A b^{2} e\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{{\left (b^{3} d^{3} - 3 \, a b^{2} d^{2} e + 3 \, a^{2} b d e^{2} - a^{3} e^{3}\right )} \sqrt{-b^{2} d + a b e}} + \frac{\sqrt{x e + d} B a b e - \sqrt{x e + d} A b^{2} e}{{\left (b^{3} d^{3} - 3 \, a b^{2} d^{2} e + 3 \, a^{2} b d e^{2} - a^{3} e^{3}\right )}{\left ({\left (x e + d\right )} b - b d + a e\right )}} + \frac{2 \,{\left (3 \,{\left (x e + d\right )} B b d + B b d^{2} + 3 \,{\left (x e + d\right )} B a e - 6 \,{\left (x e + d\right )} A b e - B a d e - A b d e + A a e^{2}\right )}}{3 \,{\left (b^{3} d^{3} - 3 \, a b^{2} d^{2} e + 3 \, a^{2} b d e^{2} - a^{3} e^{3}\right )}{\left (x e + d\right )}^{\frac{3}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x + a)^2*(e*x + d)^(5/2)),x, algorithm="giac")
[Out]